Casting

Functions and assignments will try to cast to the correct type, so Sin(someFloat) will work despite Sin requiring a double

If you want to explicitly cast you can do so like this: Sin((Double)someFloat) See for details.

Last updated 1 year ago

Functions and assignments will try to cast to the correct type, so Sin(someFloat) will work despite Sin requiring a double

If you want to explicitly cast you can do so like this: Sin((Double)someFloat) See for details.